3x^2-11x-224=0

Solution for 3x^2-11x-224=0 equation:

3x^2-11x-224=0

a = 3; b = -11; c = -224;
Δ = b2-4ac
Δ = -112-4·3·(-224)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2809}=53$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-53}{2*3}=\frac{-42}{6}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+53}{2*3}=\frac{64}{6}
=10+2/3
$